4x^2+2y^2-20=2

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Solution for 4x^2+2y^2-20=2 equation:


Simplifying
4x2 + 2y2 + -20 = 2

Reorder the terms:
-20 + 4x2 + 2y2 = 2

Solving
-20 + 4x2 + 2y2 = 2

Solving for variable 'x'.

Move all terms containing x to the left, all other terms to the right.

Add '20' to each side of the equation.
-20 + 4x2 + 20 + 2y2 = 2 + 20

Reorder the terms:
-20 + 20 + 4x2 + 2y2 = 2 + 20

Combine like terms: -20 + 20 = 0
0 + 4x2 + 2y2 = 2 + 20
4x2 + 2y2 = 2 + 20

Combine like terms: 2 + 20 = 22
4x2 + 2y2 = 22

Add '-2y2' to each side of the equation.
4x2 + 2y2 + -2y2 = 22 + -2y2

Combine like terms: 2y2 + -2y2 = 0
4x2 + 0 = 22 + -2y2
4x2 = 22 + -2y2

Divide each side by '4'.
x2 = 5.5 + -0.5y2

Simplifying
x2 = 5.5 + -0.5y2

Reorder the terms:
-5.5 + x2 + 0.5y2 = 5.5 + -0.5y2 + -5.5 + 0.5y2

Reorder the terms:
-5.5 + x2 + 0.5y2 = 5.5 + -5.5 + -0.5y2 + 0.5y2

Combine like terms: 5.5 + -5.5 = 0.0
-5.5 + x2 + 0.5y2 = 0.0 + -0.5y2 + 0.5y2
-5.5 + x2 + 0.5y2 = -0.5y2 + 0.5y2

Combine like terms: -0.5y2 + 0.5y2 = 0.0
-5.5 + x2 + 0.5y2 = 0.0

The solution to this equation could not be determined.

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